Vector Magnitude | MCQs

Explanation

To find the unit vector of A = 8i + 2j + 2k, follow these steps:

1. Find the magnitude of vector A:

   √(8² + 2² + 2²) = √(64 + 4 + 4) = √72

2. Divide each component by the magnitude:

   Unit vector â = (1/√72) × (8i + 2j + 2k)

Explanation

If a vector is given as →A = xi, its magnitude is simply |→A| = √(x²) = x (assuming x ≥ 0).