Quantum Mechanics | MCQs

Explanation

The experimental evidence that significantly contributed to the development of quantum mechanics is the Photoelectric effect. 

The photoelectric effect demonstrates that light can behave like particles (called photons) when it interacts with matter, causing electrons to be ejected from a metal surface. 

Explanation

The de-Broglie wavelength (λ) is given by the formula:

λ = h / (m × v)

Where:

h = Planck's constant = 6.626 × 10^-34 J s

m = mass of the particle = 10^-30 kg

v = velocity of the particle = 10^6 m/s

Substituting the values, we get:

λ = (6.626 × 10^-34 J s) / (10^-30 kg × 10^6 m/s)

= (6.626 × 10^-34 J s) / (10^-24 kg m/s)

= 6.626 × 10^-10 m

So, the de-Broglie wavelength associated with the particle is 6.6×10^-10m.

Explanation

The value of Planck's constant is 6.63 × 10⁻³⁴ Js.

This constant is fundamental in quantum mechanics.

It relating the energy of a photon to its frequency.

Explanation

If an electron transitions from n=6 to n=7, the percentage increase in radius is approximately 33%.

Explanation

The Compton shift is equal to the Compton wavelength at a scattering angle of 180 degrees.

Explanation

The photoelectric effect occurs at energies less than 0.5 MeV.

Explanation

The Compton effect is maximum at a scattering angle of 180 degrees.

Explanation

Explanation

Explanation