Hardy Weinberg Equilibrium | MCQs
ہارڈی وینبرگ کے توازن کی مساوات ______ ہے؟
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A. P² + 2pq + q² = 1
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B. P + 2pq + q = 0
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C. P + 2pq + q = 1
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D. None of these
Explanation
- The Hardy-Weinberg equilibrium equation is P² + 2pq + q² = 1.
- It representing the genetic frequencies of a population.
- Here, P² represents homozygous dominant.
- q² homozygous recessive.
- 2pq heterozygous individuals.
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A. 0.21
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B. 0.49
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C. None of these
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D. 0.42
Explanation
- The frequency of A1 is 0.7.
- The frequency of A2 is 0.3 (1 - 0.7).
- The proportion of heterozygous flies (A1A2) is 2pq.
- It is 2(0.7)(0.3) = 0.42.
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A. 90
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B. 36
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C. None of these
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D. 18
Explanation
- The frequency of allele a is 0.1.
- So the frequency of allele A is 0.9 (1 - 0.1).
- The heterozygous genotype (Aa) frequency is 2pq.
- It is 2(0.9)(0.1) = 0.18 or 18%.
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