Electrostatic Force Calculation | MCQs

Explanation

The magnitude of the force between two unit positive charges (each with a charge of 1 Coulomb) separated by a distance of 1 meter in a vacuum is given by Coulomb's Law:

F = k × (q1 × q2) / r^2

where:

F = force (in Newtons)

k = Coulomb's constant (approximately 8.98755 × 10^9 N m^2 C^2)

q1 and q2 are the charges (in Coulombs)

r is the distance between the charges (in meters)

Plugging in the values, we get:

F ≈ (8.98755 × 10^9 N m^2 C^2) × (1 C × 1 C) / (1 m)^2

F ≈ 8.98755 × 10^9 N

F ≈ 9 × 10^9 N (approximately)

Since 1 Newton is equal to 10^9 N (by definition), we can simplify the answer to:

F ≈ 1 N (approximately)