The magnitude of force between two unit positive charges when the distance between them is 1m would be?
Answer: 1N
Explanation
The magnitude of the force between two unit positive charges (each with a charge of 1 Coulomb) separated by a distance of 1 meter in a vacuum is given by Coulomb's Law:
F = k × (q1 × q2) / r^2
where:
F = force (in Newtons)
k = Coulomb's constant (approximately 8.98755 × 10^9 N m^2 C^2)
q1 and q2 are the charges (in Coulombs)
r is the distance between the charges (in meters)
Plugging in the values, we get:
F ≈ (8.98755 × 10^9 N m^2 C^2) × (1 C × 1 C) / (1 m)^2
F ≈ 8.98755 × 10^9 N
F ≈ 9 × 10^9 N (approximately)
Since 1 Newton is equal to 10^9 N (by definition), we can simplify the answer to:
F ≈ 1 N (approximately)
