Explanation
Bond order = ½ (Number of bonding electrons − Number of antibonding electrons)
For H₂:
- Bonding electrons = 2
- Antibonding electrons = 0
Bond order = ½ (2 − 0) = 1
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A. None of the above
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B. Two
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C. Zero
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D. One
Explanation
To calculate the bond order of O2²⁻, we need to construct a molecular orbital diagram.
The molecule has 18 electrons (12 from oxygen atoms and 6 from the negative charge).
These electrons are filled into the orbitals, starting from the lowest energy level.
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