What is the energy stored in a capacitor if capacitance is 4 μF and voltage is 100 V?
Answer: 0.02 J
Explanation
To find the energy stored in a capacitor, we use the formula:
E=1/2CV^2
Where:
-
C=4μF=4×10^−6F
-
V=100V
Calculation:
E=1/2×4×10^−6×(100)^2
E=1/2×4×10^−6×10000
E=2×10^−6×10000
=0.02J
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