Capacitance of a parallel plate capacitor in the presence of insulator having dielectric constant εr is C. If the dielectric is removed from plates, then new capacitance will be
Answer: C / εr
Explanation
- Capacitance with dielectric: C = εr · C₀, where C₀ is the capacitance without dielectric.
- If the dielectric is removed, capacitance becomes C₀ = C / εr.
So, the new capacitance is C divided by εr.
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