The total capacitance of a 300 mF capacitor and a 600 mF in series _____?
The total capacitance of a 300 mF capacitor and a 600 mF in series _____?
Explanation
When capacitors are connected in series, the total capacitance (C_total) is given by:
1/C_total = 1/C1 + 1/C2
Given:
C1 = 300 mF
C2 = 600 mF
1/C_total = 1/300 + 1/600
= (2 + 1) / 600
= 3 / 600
= 1 / 200
C_total = 200 mF