Thermal Motion | MCQs

Explanation

The average translational kinetic energy of a molecule is given by:

(3/2)kT = (3/2) × (1.38 × 10^-23 J/K) × T

Since the temperature is the same for both O2 and N2 molecules, the average translational kinetic energy will be the same:

0.048 eV = (3/2)kT

The mass of the molecule does not affect the average translational kinetic energy.

Therefore, the translational kinetic energy of N2 molecules at the same temperature is also:

0.048 eV