The set L = {x, y, z} has 3 elements: x, y, z.
The proper subsets are:
1. {x}
2. {y}
3. {z}
4. {x, y}
5. {x, z}
6. {y, z}
7. {}
There are 7 proper subsets.
The number of subsets of a set with n elements is 2^n.
Here, X has 5 elements.
Number of subsets = 2^5
= 32
A singleton set has only one element (e.g., {a}).
The only proper subset is the empty set (∅), so it has one proper subset.
If A is a subset of B (A ⊂ B), then every subset of A is also a subset of B.
This means the power set of A (P(A)) is a subset of the power set of B (P(B)).
The empty set ∅ has exactly one subset, which is itself (∅).
To find the number of subsets of a set A:
Number of subsets = 2^n
where n is the number of elements in the set.
In this case:
A = {a, e, i, o, u}
n = 5
Number of subsets = 2^5 = 32
A power set contains all possible subsets of a given set, including the empty set and the set itself.
Example: If set = {a, b}, then power set = {∅, {a}, {b}, {a, b}}.
Here, A = {a, b, c} has 3 elements, so:
Number of subsets = 2^3
= 8
The subsets are:
{}, {a}, {b}, {c}, {a, b}, {a, c}, {b, c}, {a, b, c}
Number of subsets =2n=23=8.
the number of possible subsets as 2^3 = 8.
Let's list all the subsets of set S:
- Subset 1: {} (the empty set)
- Subset 2: {a}
- Subset 3: {b}
- Subset 4: {c}
- Subset 5: {a, b}
- Subset 6: {a, c}
- Subset 7: {b, c}
- Subset 8: {a, b, c}
The possible number of subsets of a set with nnn elements, including the empty set and the universal set, is 2n2^n.
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