Series Capacitance | MCQs
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A. ¼ µF
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B. 3 µF
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C. 2 µF
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D. 4 µF
Explanation
When two capacitors of equal capacitance (C) are connected in series, the equivalent capacitance (Ceq) is half the value of one capacitor:
Ceq = (C × C) / (C + C) = (C × C) / 2C = C/2
In this case, C = 8 µF, so:
Ceq = 8 µF / 2 = 4 µF
Therefore, the equivalent capacitance of the two 8 µF capacitors connected in series is 4 µF.
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