Projectile Motion | MCQs

Explanation

Explanation

At the highest point of a projectile's motion:

- Its velocity is purely horizontal (vertical component = 0).

- Its acceleration is still vertically downward due to gravity.

So, the velocity vector is horizontal, and the acceleration vector is vertical ⇒ they are perpendicular.

∴ Angle between velocity and acceleration = 90°  

Explanation

The ball will fall behind him.

When the man throws the ball vertically upward, it maintains the horizontal velocity of the train due to inertia.

However, the train continues to move forward while the ball is in the air.

As the ball falls back down, it will have traveled a shorter horizontal distance compared to the train,

Resulting in it landing behind the man where he originally threw it. 

Explanation

Maximum height is reached when vertical velocity becomes zero.  

Using the kinematic equation:  

v² = u² - 2gh, with final v = 0,  

h = (vi² * sin²θ) / 2g.

Explanation

In ideal projectile motion, gravity is the only significant force acting downward on the object.

Air resistance is usually neglected, so gravitational force controls the curved path.

Explanation

A stone thrown from a height follows a projectile motion, which traces a parabolic path under gravity.

This occurs due to the combination of constant horizontal velocity and accelerated vertical motion.

Explanation

In projectile motion, the velocity is maximum at the point of projection and just before hitting the ground,

Because that’s where the full initial speed is present (both vertical and horizontal components).

At the highest point, the vertical component becomes zero,

And only the horizontal velocity remains, so the overall speed is less than at the point of projection.

Explanation

In projectile motion, the vertical velocity changes due to gravity.

It increases downward and decreases upward, so it varies at every point.

Explanation

Step 1: Use projectile motion

The maximum range of a projectile (ignoring air resistance) is given by:

R=v^2sin(2θ)/g​

The maximum range occurs when θ=45∘the value is maximum at (i.e.,sin(90∘)=1).

Step 2: Plug in values

• $v = 12 text{m/s}$

• g=10 m/s^2

R=12^2⋅1 ​/ 10 

= 144/10

​=14.4 meters

Explanation

h = u²/2g = (16)² / (2 × 9.8) = 256 / 19.6 = 13.06 ≈ 13.1 m.