Maximum Height | MCQs

Explanation

When a man throws a ball to the maximum height (h), the initial velocity (v₀) is entirely vertical.

The maximum height (h) is given by:

h = v₀² / (2g)

where g is the acceleration due to gravity.

Now, when the man throws the same ball to the maximum horizontal distance, the initial velocity (v₀) is entirely horizontal.

The maximum horizontal distance (R) is given by:

R = v₀² / g

Substituting the expression for v₀² from the first equation:

R = 2h

Explanation

Explanation

Step 1: Use projectile motion

The maximum range of a projectile (ignoring air resistance) is given by:

R=v^2sin(2θ)/g​

The maximum range occurs when θ=45∘the value is maximum at (i.e.,sin(90∘)=1).

Step 2: Plug in values

• $v = 12 text{m/s}$

• g=10 m/s^2

R=12^2⋅1 ​/ 10 

= 144/10

​=14.4 meters

Explanation

h = u²/2g = (16)² / (2 × 9.8) = 256 / 19.6 = 13.06 ≈ 13.1 m.