Ozonolysis Reaction | MCQs
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A. 2-pentanone
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B. 7-Heptanone
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C. 3-Pentanone and Ethanal
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D. Pentanal
Explanation
Ozonolysis cleaves the double bond in 3-Ethyl-2-pentene, forming two carbonyl compounds.
The double bond is between C2 and C3:
CH3–CH=CH–CH(CH2CH3)–CH3
On ozonolysis, it breaks at the double bond, yielding:
- Ethanal (CH3CHO) from the CH= part
- 3-Pentanone (CH3COCH2CH2CH3) from the rest
✅ Correct: 0 |
❌ Wrong: 0 |
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