To check if a number is exactly divisible by 4, we can check if the last two digits form a number that is divisible by 4.
2000: Last two digits are 00, which is divisible by 4.
Since 2000 ends in 00, it is exactly divisible by 4.
A number is exactly divisible by 5 if it ends in 0 or 5.
230590 ends in 0, so it is divisible by 5.
Given equation: x^2 - 3kx + 4k^2 = 0.
Sum of roots = 3k, Product of roots = 4k^2.
Sum of squares of roots = (sum of roots)^2 - 2(product of roots)
= (3k)^2 - 2(4k^2)
= 9k^2 - 8k^2
= k^2.
Given sum of squares = one of the options.
If sum of squares = 1, then k^2 = 1, so k = ±1
Given equation:
x² - 5x + 6 = 0
Factor the quadratic equation:
(x - 2)(x - 3) = 0
This gives us:
x - 2 = 0 or x - 3 = 0
x = 2 or x = 3
The roots of the equation are x = 2 and x = 3.
1 + 2 + 3 + ... + n = 15
This is an arithmetic series. Use the formula:
n(n + 1)/2 = 15
→ Multiply both sides by 2:
n(n + 1) = 30
Try n = 5:
5(6) = 30
So, n = 5
Now calculate:
1³ + 2³ + 3³ + ... + n³
Use formula:
[n(n + 1)/2]² = [5×6/2]² = (15)² = 225
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