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A. Mass of the body
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B. Angle on which it is thrown
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C. Mass of earth
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D. Both mass of the body and the angle at which it is thrown
Explanation
The escape velocity of a body in the gravitational field of Earth is primarily dependent on the mass of the Earth and the radius of the Earth.
It does not depend on the mass of the body or the angle at which it is thrown.
The formula for escape velocity 𝑣e is given by:

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A. 11.2 km/s
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B. 112 km/s
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C. None of these
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D. 3.7 km/s
Explanation
Escape velocity (vₑ) is given by:
vₑ = √(2GM/r)
where:
G = gravitational constant
M = mass of the planet
r = radius of the planet
Given:
M₂ = 1000M₁ (mass of the new planet is 1000 times that of Earth)
r₂ = 10r₁ (radius of the new planet is 10 times that of Earth)
Escape velocity on the new planet (vₑ₂) is:
vₑ₂ = √(2GM₂/r₂)
= √(2G(1000M₁)/(10r₁))
= √(200G(M₁/r₁))
= √200 × √(2GM₁/r₁)
= √200 × vₑ₁
Given vₑ₁ = 11.2 km/s:
vₑ₂ ≈ √200 × 11.2 km/s
≈ 112 km/s
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A. √g/R
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B. √gR
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C. g/R
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D. gR
Explanation
The critical velocity (vc) is the minimum velocity an object must have to orbit the Earth without falling to the ground.
It is given by the formula:
vc = √(gR)
where:
- g is the acceleration due to gravity (approximately 9.8 m/s²)
- R is the radius of the Earth (approximately 6,371 kilometers)
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A. 1/√2
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B. 2
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C. √2
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D. 1/2
Explanation
Orbital velocity is 1/√2 times escape velocity, derived from gravitational motion equations.
چھوٹے سوراخ سے گیس کے انووں سے فرار _____ کہا جاتا ہے؟
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A. None of these
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B. Effusion
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C. Osmosis
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D. Diffusion
Explanation
Effusion is the process by which gas particles pass through a tiny hole without collisions between particles.It is described by Graham’s Law, which relates effusion rate to molar mass.
اگر زمین کا رداس اس کی اصل قدر کا ایک چوتھائی رہ جائے تو فرار کی رفتار کا کیا ہوگا؟
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A. Doubled
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B. Quadrupled
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C. No change
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D. Halved
Explanation
If the radius of the Earth is reduced to one-fourth of its original value, the escape velocity will be quadrupled.

نیپچون کے فرار کی رفتار تقریباً ہے؟
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A. 21.5 km/s
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B. 23.5 km/s
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C. 19.5 km/s
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D. 25.5 km/s
Explanation
The escape velocity of Neptune is approximately 23.5 km/s.
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