Centripetal Force | MCQs

Explanation

Centripetal force is any force that keeps an object moving in a circular path, directed toward the center of the circle.

Tension in a string, gravitational force (like planets orbiting), and friction (like a car turning) can all provide centripetal force.

Explanation

Explanation

A body moving in a circular path with constant speed has variable acceleration. 

While the speed remains constant, the direction of the velocity vector is constantly changing as the body moves around the circle.

Since acceleration is the rate of change of velocity, and velocity is changing (even though speed is constant),

The body experiences a constant magnitude of acceleration

But the direction of that acceleration changes at every point on the circle.

This makes the acceleration variable. 

Explanation

Centripetal force acts perpendicular to the direction of motion in circular motion.

Since work = force × displacement × cos(θ), and θ = 90°, the work done is zero.

Explanation

Explanation

The friction between the car's tires and the road provides the necessary centripetal force that keeps the car moving in a circular path.

This frictional force acts towards the center of the circular path, allowing the car to change direction without sliding out.

Explanation

• A stone whirling in a horizontal circle on the end of a string is a classic example of a conical pendulum, a type of physical system that demonstrates principles of circular motion, centrifugal force, and angular momentum.
• The string traces out a cone-shaped path, hence the name "conical pendulum".
• This is different from a simple pendulum, which swings back and forth in a vertical plane.

Explanation

In circular motion, the centripetal force  𝐹 required to keep an object moving in a circular path is given by the formula:

𝐹= 𝑚 𝑣^2/ 𝑟

Where:

m is the mass of the object,

v is the velocity of the object,

r is the radius of the circular path.

If the velocity v is doubled, the centripetal force becomes:

F ′ =  m(2v) ^2/r = 4mv ^2/r =4F

This means that if the velocity is doubled, the force will be four times the original, not twice or half the original.

Therefore, neither of the options provided is correct.

Explanation

The centripetal force necessary to keep the racing car in its circular path is indeed provided by friction between the tires of the car and the track.

Concept:

When the car is moving in a circular path, it experiences an inward acceleration towards the center of the circle.

This acceleration is called the centripetal acceleration.

According to Newton's second law of motion, the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, the net force is the centripetal force, and the centripetal acceleration can be calculated using the formula:

a_c = v^2 / r

Where:

- a_c is the centripetal acceleration

- v is the speed of the car

- r is the radius of the circular track

Substituting the given values into the formula:

a_c = (50.0 m/s)^2 / 250 m

Simplifying the equation:

a_c = 2500 m^2/s^2 / 250 m

a_c = 10 m/s^2

The centripetal force required to keep the car in its circular path is equal to the product of the car's mass and the centripetal acceleration.

Using the given mass of the car:

F = (2.00 x 10^3 kg) * (10 m/s^2)

Simplifying the equation:

F = 2.00 x 10^4 N

Therefore, the centripetal force necessary to keep the car in its circular path is provided by friction and its value is 2.00 x 10^4 Newtons.

Explanation

To calculate the force exerted by the pavement on the tires, we can use the centripetal force formula:

Force (F) = (Mass (m) * Velocity squared (v^2)) / Radius (r)

Given:

Mass (m) = 1000 kg

Velocity (v) = 10 m/s

Radius (r) = 10 m

 Calculate the centripetal force (F):

Using the formula, F = (m * v^2) / r, we can substitute the given values to find the force:

F = (1000 kg * (10 m/s)^2) / 10 m

F = 100,000 N / 1.0 x 10^4 N