Explanation

Explanation

When capacitors are connected in series, the total capacitance (C_total) is given by:

1/C_total = 1/C1 + 1/C2

Given:

C1 = 300 mF

C2 = 600 mF

1/C_total = 1/300 + 1/600

= (2 + 1) / 600

= 3 / 600

= 1 / 200

C_total = 200 mF

Explanation

Explanation

Explanation

Explanation

To find the final temperature, we can use the principle of heat transfer:

Heat lost by lead = Heat gained by water

Given:

Specific heat of lead (c Pb) = 0.030 cal/g°C

Mass of lead (m Pb) = 300 g

Initial temperature of lead (T Pb) = 100°C

Mass of water (m w) = 100 g

Initial temperature of water (T w) = 70°C

Specific heat of water (c w) = 1 cal/g°C (approximately)

Let the final temperature be T f.

Heat lost by lead = m Pb × c Pb × (T Pb - T f)

= 300 × 0.030 × (100 - T f)

Heat gained by water = m w × c w × (T f - T w)

= 100 × 1 × (T f - 70)

Equating the two expressions:

300 × 0.030 × (100 - T f) = 100 × 1 × (T f - 70)

Simplifying the equation:

9(100 - T f) = 100T f - 7000

900 - 9T f = 100T f - 7000

109T f = 7900

T f ≈ 72.5°C

Explanation

Explanation

Explanation

Explanation