Given:
Radius (r) = 13 cm
Distance from center to chord (d) = 5 cm
Let's draw a perpendicular from the center to the chord. This will bisect the chord.
Using the Pythagorean theorem:
r² = d² + (half chord)²
13² = 5² + (half chord)²
169 = 25 + (half chord)²
(half chord)² = 169 - 25
= 144
half chord = √144
= 12 cm
Length of chord = 2 × half chord
= 2 × 12
= 24 cm
A circle can have an infinite number of tangents.
Since a circle is defined as a set of points equidistant from a fixed point,
And each point on the circle can have a tangent line, there are infinitely many possible tangent lines.
Let the circumference of the circle = perimeter of the square = P
- Circumference of circle = 2πr
- Perimeter of square = 4a (a = side of square)
So, 2πr = 4a ⇒ a = (πr)/2
- Area of circle = πr²
- Area of square = a² = (πr/2)² = (π²r²)/4
Now compare:
πr² (circle) vs. (π²r²)/4 (square)
Divide both sides:
(πr²) / ((π²r²)/4) = 4/π > 1 ⇒ area of circle > area of square.
Circumference =2πr.
∴2πr=31.4.
2×3.14×r=31.4.
r=5cm.
Area =πr2.
Area =3.14×(25)2
=78.5cm2.
The total angle around a circle is always 360 degrees.
This represents a full rotation or complete turn.
A circum-circle is a circle that passes through all the vertices of a triangle.
Its center is called the circumcenter.
Because a tangent can be drawn at any point on the circumference of the circle, each touching it at exactly one point.
The area of a circle can be expressed in terms of its circumference C as:
A = C^2 / 4π
This is because the circumference C is related to the radius r by:
C = 2πr
And the area A is related to the radius r by:
A = πr^2
Substituting the expression for r in terms of C, we get:
A tangent line intersects a circle at 1 point.
This is because a tangent touches the circle at exactly one point without crossing it.
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