When 5/3 is divided, it gives 1.666..., where 6 repeats infinitely.
Since the decimal never ends but follows a repeating pattern, it is non-terminating and recurring.
To find (A ∪ B)':
First, find A ∪ B:
A ∪ B = {2, 3, 4} ∪ {1, 3, 5}
= {1, 2, 3, 4, 5}
Now, find the complement of A ∪ B:
(A ∪ B)' = U - (A ∪ B)
= {1, 2, 3, 4, 5} - {1, 2, 3, 4, 5}
= {}
A proper fraction has a numerator smaller than the denominator, meaning its value is less than 1.
7/8 is the only one that meets this condition.
Multiply the numerators:
Multiply the denominators:
2/9×4/9=8/18
To find the smallest ratio, we need to simplify the fraction 0.35/0.65.
First, convert the decimals to fractions:
0.35 = 35/100 = 7/20
0.65 = 65/100 = 13/20
Now, divide the fractions:
(7/20) ÷ (13/20) = 7/13
So, the smallest ratio is 7/13.
The complement of a null set (∅) includes all elements of the universal set (U).
Since ∅ contains nothing, its complement is everything in U, so ∅' = U.
Let the original bill be x. After deduction of 20%, the remaining amount is Rupees 100. Expressing given information in mathematical form.
x - 20% of x = 100
Solving the mentioned mathematical equation to find the value of x.
x - 20/100x = 100
x - x/5 = 100
Taking L.C.M., which is 5.
5x - x = 5*100
Performing subtraction and multiplication.
4x = 500
Performing division to find the value of x.
x = 500/4
x = Rupees 125
So, the original bill is Rupees 125.
To solve the equation, follow the order of operations:
3 × 4 = 12
12 × 5 = 60
60 ÷ 5 = 12
12 × 0.012 = 0.144
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