To find b, substitute a=2 into the equationa=b+4:
2=b+4
Subtract 4 from both sides
2−4=b
b=−2
2x+3=3x−2
First, let's move all terms involving x to one side of the equation. We can do this by subtracting 2x from both sides:
2x+3−2x=3x−2−2x
3=x−2
Next, let's isolate x by adding 2 to both sides:
3+2=x−2+2
5=x
So, the solution to the equation is x=5.
x+y =13 if y=18 then x is -5
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x+y =13
y=18x + 18 = 13
x = 18-13
x= -5
Step 1: Determine the value of each power of j
j¹⁰ = (j²)⁵ = (-1)⁵ = -1.
j¹⁰⁰ = (j²)⁵⁰ = (-1)⁵⁰ = 1.
j¹⁰⁰⁰ = (j²)⁵⁰⁰ = (-1)⁵⁰⁰ = 1.
Step 2: Calculate the expression
1 + j¹⁰ + j¹⁰⁰ - j¹⁰⁰⁰ = 1 + (-1) + 1 - 1 = 0.
Let x be that number
then according to the given condition
(7×x)−3=53
so ,7x−3=53
7x=56
so x=8
so the number is 8
7X-3=53 7X=56 X=8
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RY18012023
To solve for y in the equation 0.15y=15, we can divide both sides by 0.15:
y = 15/0.15
Calculating this gives:
y = 0.15 /15
y =100
The equation is separable:
dy/dx = –y
⇒ dy/y = –dx
⇒ ∫(1/y) dy = ∫(–1) dx
⇒ ln|y| = –x + C
⇒ y = Ce⁻ˣ (where C is the constant of integration)
Given the equation 20 = 3x + 8:
Step 1: Subtract 8 from both sides.
20 - 8 = 3x
12 = 3x
Step 2: Divide both sides by 3.
x = 12 / 3
x = 4
It looks like there’s a small mistake in the equation format.
Assuming the intended equation is:
x−5=10
Let's solve for x:
1; Add 5 to both sides to isolate
x=10+5=15