C's mother was four times as old as C ten years ago After 10 years she will be twice as old as C is now How old is C now?
Answer: 25
Explanation
Given:
-
Ten years ago, C's mother was 4 times as old as C:
10 years ago, C = 15 → mother = 4×15 = 60 → Now = 70
After 10 years, mother = 80 → 2×25 = 50
This question appeared in
Past Papers (4 times)
FPSC 5 Years Past Papers Subject Wise (Solved With Details) (1 times)
FPSC Past Papers (1 times)
Inspector Customs, Intelligence Officer Past Papers, Syllabus (2 times)
This question appeared in
Subjects (1 times)
MATHS MCQS (1 times)
Related MCQs
- The age of mother is two times the age of her daughter., 2 years after the sum of their ages will be 49.. Find the age age of daughter after two years.
- The mother's age is 3 times that of her son. After 8 years, the mother's age will be _____?
- Three years ago, the age of a father was three times the age of his son. If the sum of their current ages is 70 years, what is the present age of the son?
- A sum of money doubles itself at compound interest in 15 years. In how many years it will become eight times?
- A man is 41 years old and his son is 9 years old. In how many years will the father be three times as old as the son?
- What is Aslam's present age, if after 20 years his age will be 10 times his age 10 years back?
- The sum of the present ages of a father and his son is 60 years. Six years ago father's age was five times the age of the son After six years son's age will be
- The present age of Vinay's mother is three times the present age of Vinay. After 5 years, sum of their ages will be 70 years. Find their present ages.
- If a sum on compound interest becomes 3 times in a certain number of years, then with the same interest rate, in how many years will it become 27 times?
- Ages of the two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old as the younger one, find their present ages.