The sum of two numbers is 40. One of the numbers exceeds the other by 12. The required numbers are ______?

Answer: 26, 14
Explanation
Let's denote the smaller number as x and the larger number as x + 12.
Given:
x + (x + 12) = 40
Combine like terms:
2x + 12 = 40
Subtract 12 from both sides:
2x = 28
Divide by 2:
x = 14
The larger number is x + 12 = 14 + 12 = 26
The numbers are 26 and 14.
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