The sum of the squares of two numbers is 100. One number is 2 more than the other. Find the larger number?

The sum of the squares of two numbers is 100. One number is 2 more than the other. Find the larger number?

Explanation

Let the smaller number be x.

The larger number is x + 2.

Given:

x² + (x + 2)² = 100

x² + x² + 4x + 4 = 100

2x² + 4x - 96 = 0

x² + 2x - 48 = 0

(x + 8)(x - 6) = 0

x = -8 or x = 6

If x = -8, larger number = -8 + 2 = -6

If x = 6, larger number = 6 + 2 = 8