A father is twice as old as his son. 20 years ago, the age of the father was 12 times the age of the son. The present age of the father is....

32 years

45 years

22 years

44 years

let the son’s age be “x”

fathers age=2x

son’s age before 20 years = x-20

father’s age before 20 years= 12(x-20)

2x-20=12x-240

-20+240=12x-2x

220=10x

x=22

son’s age=22

father’s age=44

ND22-1-2023