Three consecutive integers are listed in increasing order. If there sum is 102, what is the second integer in the list?
Answer: 34
Explanation
the integers are consecutive, the middle integer must equal the “average”, or 102/3 = 34.
Therefore, the integers are 32, 34, and 36.
let three consecutive integers= x ,x+1,x+2 According to condition X+(x+1) +( x+2)=102 3x+ 3= 102 3x= 102-3 3x= 99 X= 99/3 X = 33 X+1= 33+1 X+1= 34 X+2= 34+2 X+2= 36 33, 34, 36 answer
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ND04-12-2022
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