How many tiles of dimension 10 square inch are required to cover a floor of dimension of 5 feet by 4 feet?
Answer: 288
Explanation
To find the total number of tiles required, we need to convert the floor dimensions from feet to inches and then divide the total area by the area of a single tile.
Floor dimensions:
5 feet = 5 x 12 = 60 inches (length)
4 feet = 4 x 12 = 48 inches (width)
Total area = length x width = 60 x 48 = 2880 square inches
Tile dimension:
10 square inches
Now, divide the total area by the tile area:
2880 ÷ 10 = 288
So, 288 tiles of dimension 10 square inches are required to cover the floor.
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