The sum of two numbers, if one number is two third of second is equal to 45. Find the smaller number?

Given that one number is two-thirds of the second:

x = (2/3)y

The sum of the two numbers is 45:

x + y = 45

Substitute x from the first equation:

(2/3)y + y = 45

Combine like terms:

(5/3)y = 45

Multiply both sides by 3:

5y = 135

Divide by 5:

y = 27

Now, find the smaller number x:

x = (2/3)y

x = (2/3) × 27

x = 18