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In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.1. What is the percentage of the population that is heterozygous for this allele?

In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.1. What is the percentage of the population that is heterozygous for this allele?

Explanation
  • The frequency of allele a is 0.1.
  • So the frequency of allele A is 0.9 (1 - 0.1).
  • The heterozygous genotype (Aa) frequency is 2pq.
  • It is 2(0.9)(0.1) = 0.18 or 18%.