30 grams of acetic acid reacts with excess of ethyl alcohol to form 40 grams of ethyl acetate during esterification then percentage yield of ester is?

ایسٹریفیکیشن کے دوران 30 گرام ایسٹک ایسڈ زیادہ ایتھائل الکحل کے ساتھ رد عمل ظاہر کرتا ہے اور 40 گرام ایتھیل ایسٹیٹ بناتا ہے تو ایسٹر کی فیصدی پیداوار ہے؟

90.9%

85.9%

50%

80%

Explanation

First, we calculate the number of moles of acetic acid used:

Number of moles of acetic acid = mass of acetic acid / molar mass of acetic acid

Number of moles of acetic acid = 30 g / 60 g/mol = 0.5 moles

Since the reaction is 1:1 between acetic acid and ethyl acetate, the number of moles of ethyl acetate produced is also 0.5 moles.

Now, we can calculate the theoretical yield of ethyl acetate:

Theoretical yield of ethyl acetate = number of moles of ethyl acetate * molar mass of ethyl acetate

Theoretical yield of ethyl acetate = 0.5 moles * 88 g/mol = 44 grams

Now, we can calculate the percentage yield:

Percentage yield = (actual yield / theoretical yield) * 100%

Percentage yield = (40 g / 44 g) * 100%

Percentage yield ≈ 90.9%

So, the percentage yield of the ester is approximately 90.9%.