How many moles of NaCl are produced from 16.5g of HCl, according to the neutralization reaction? HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(I)

How many moles of NaCl are produced from 16.5g of HCl, according to the neutralization reaction? HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(I)

Explanation

The molar mass of HCl is 36.5 g/mol. To find the moles of HCl:

Moles of HCl= 36.5g/mol16.5g =0.452 moles

Since the reaction is 1:1, 0.452 moles of HCl will produce 0.452 moles of NaCl.