A 30 cm long string with one end clamped and the other free is vibrating in its second harmonic. The wavelength of the constituent travelling waves is
Answer: 40 cm
Explanation
Given:
- Length of string, L = 30 cm
- In 2nd harmonic, L = 3λ/4
Solving:
30 = (3/4)λ
⇒ λ = (4 × 30) / 3 = 40 cm
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