A straight wire of length 0.20 m moves at a steady speed of 3.0 ms^-1 at night angles to the magnetic field of flux density 0.10 T. The EMF induced across ends of wire is?
Answer: 0.06 V
Explanation
The EMF induced across the ends of a wire moving through a magnetic field can be calculated using the formula:
E = Blv
Where:
- E is the induced EMF in volts
- B is the magnetic flux density in teslas
- l is the length of the wire in meters
- v is the velocity of the wire in meters per second
Given:
B = 0.10 T
l = 0.20 m
v = 3.0 m/s
Substituting the values into the formula, we get:
E = 0.10 x 0.20 x 3.0
E = 0.06 V
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