The de-Broglie wavelength associated with a particle moving at 10^6 m/s and having mass 10^-30 kg?

1.9×10^-5m

7.2×10^-8m

6.6×10^-10m

1.5×10^9m

The de-Broglie wavelength (λ) is given by the formula:

λ = h / (m × v)

Where:

h = Planck's constant = 6.626 × 10^-34 J s

m = mass of the particle = 10^-30 kg

v = velocity of the particle = 10^6 m/s

Substituting the values, we get:

λ = (6.626 × 10^-34 J s) / (10^-30 kg × 10^6 m/s)

= (6.626 × 10^-34 J s) / (10^-24 kg m/s)

= 6.626 × 10^-10 m

So, the de-Broglie wavelength associated with the particle is 6.6×10^-10m.