While launching a rocket of mass 2×10^4 kg, a force of 5×10^5 N is applied for 20s. Calculate the velocity attained by the rocket at the end of 20s?
Answer: 500m/s
Explanation
To calculate the velocity attained by the rocket, we can use the equation:
F × t = m × Δv
where:
F = force applied (5 × 10^5 N)
t = time (20 s)
m = mass of the rocket (2 × 10^4 kg)
Δv = change in velocity (final velocity - initial velocity)
Since the rocket starts from rest, the initial velocity is 0. Therefore, Δv = final velocity.
Rearranging the equation to solve for Δv, we get:
Δv = F × t / m
= (5 × 10^5 N) × (20 s) / (2 × 10^4 kg)
= 500 m/s
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