The distance between the adjacent atomic planes in CaCO3 is 0.3nm. The smallest Bragg scattering for 0.03nm X-ray is?
Answer: 2.9°
Explanation
To find the smallest Bragg scattering angle, we can use Bragg's law:
2d sin(θ) = nλ
where d is the distance between the atomic planes, θ is the scattering angle, n is an integer (which is 1 for the smallest angle), and λ is the wavelength of the X-ray.
Given:
d = 0.3 nm
λ = 0.03 nm
Rearranging Bragg's law to solve for θ, we get:
sin(θ) = λ / (2d)
= 0.03 nm / (2 × 0.3 nm)
= 0.05
θ = arcsin(0.05)
≈ 2.9°
This question appeared in
Past Papers (4 times)
Lecturer Physics Past Papers and Syllabus (1 times)
SPSC 25 Years Past Papers Subject Wise (Solved) (2 times)
SPSC Past Papers (1 times)
This question appeared in
Subjects (1 times)
EVERYDAY SCIENCE (1 times)
Related MCQs
- In a transverse wave, the ______ is the distance b/w its two adjacent crests or troughs?
- Which of the following has smallest atomic radius?
- Distance between Earth and Sun is smallest in month of ___ ?
- Resolution of a microscope is defined as the smallest distance between _____ points.
- After the discovery of atomic number, scientists noted that atomic number can be used to arrange elements in a systematic way. The atomic number was discovered by _______?
- In Bragg's equation (2dSinθ = nλ), ‘n’ represents:
- Bragg's equation is a consequence of _____?
- Which type of the following chemical equation is? CaO + CO2 →CaCO3?
- What is the mass of 1 mole of calcium carbonate (CaCO3)?
- Light scattering in colloid system is due to ___
