A torque of 2 x 10^-4 Nm is applied to produce an angular acceleration of 4rad/s^2 in a rotating body. What is the moment of inertia of the body?
Answer: 0.5 × 10^-4 kgm^2
Explanation
To find the moment of inertia (I) of the rotating body, we can use the formula:
τ = I × α
where τ is the torque, I is the moment of inertia, and α is the angular acceleration.
Given:
τ = 2 × 10^-4 Nm
α = 4 rad/s^2
Rearranging the formula to solve for I:
I = τ / α
= (2 × 10^-4 Nm) / (4 rad/s^2)
= 0.5 × 10^-4 kgm^2
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