What will happen to orbital speed of a satellite if its orbital radius (R+h) is half of its initial value?
Answer: Increase √2 times
Explanation
The orbital speed (v) of a satellite is given by:
v = √(GM / (R + h))
If the orbital radius (R + h) is halved:
v' = √(GM / ((R + h) / 2))
= √(2GM / (R + h))
= √2 * √(GM / (R + h))
= √2 * v
So, the orbital speed will increase √2 times.
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