A small flashlight bulb draws 300 mA from its 1.5 V battery. What is the resistance of the bulb?
Answer: 5 Ω
Explanation
Step 1: Recall Ohm's Law
V = IR, where V is voltage, I is current, and R is resistance.
Step 2: Convert current to amperes
300 mA = 0.3$ A
Step 3: Calculate the resistance
R = V/I = 1.5/0.3 = 5 Ω
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