A circular disc of mass M and radius R is rotating about its axis with uniform speed. Its kinetic energy is?
Answer: ½ × Mv²
Explanation
Rotational kinetic energy of a disc about its center:
K.E = (1/2) I ω², where I = moment of inertia.
For a disc, I = (1/2)MR²,
So, K.E = ½ × (½ MR²) × ω² = ¼ MR²ω²
If linear velocity v = Rω, then
K.E = ¼ Mv²
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