27 grams of Al will react completely with how much mass of O2 to produce Al₂O₃?

27 grams of Al will react completely with how much mass of O2 to produce Al₂O₃?

Explanation
Balanced equation:
4Al + 3O₂ → 2Al₂O₃
Molar masses: Al = 27 g/mol, O₂ = 32 g/mol
108 g Al reacts with 96 g O₂ → 27 g Al reacts with 24 g O₂.
Proportion:
96/108 × 27 = 24 g