Ten identical steel balls, each with a mass of 27 g, are immersed in a measuring cylinder initially containing a certain volume of water. The water level rises by 50 cm³ after immersing the balls. What is the density of the steel?

0.90 gm/cm^3

8.1 gm/cm^3

9.0 gm/cm^3

13.5 gm/cm^3

To find the density of the steel balls, we need to use the formula for density:

Density = Mass/Volume

1. Calculate the total mass of the steel balls:

Each ball has a mass of 27 g, and there are 10 balls.

Total mass = 10 x 27 = 270 g

2. Calculate the volume displaced by the steel balls:

The initial volume of water is 20 cm^3

The final volume of water is 50 cm^3

The volume displaced by the steel balls is:

Volume displaced = 50 cm^3 - 20 cm^3 = 30 cm^3

3. Calculate the density of the steel:

Using the total mass and the volume displaced:

Density = 270 g / 30cm,^3 = 9.0 g/cm^3

Therefore, the density of the steel is 9.0 g/cm^3.