Which term of the AP 2, 11, 20, 29, _______is 290?
Which term of the AP 2, 11, 20, 29, _______is 290?
Explanation
In an arithmetic progression (AP), the nth term is given by the formula
Tn=a+(n−1)⋅d
Where:
a is the first term
d is the common difference,
n is the term number.
For the given AP:
First term a=2,
Common difference d=11−2=9,
We are looking for n when the term is 290.
Let the given AP contain n terms.
Tn = 290
=> a + (n – 1)d = 290
=> 2 + (n – 1)9 = 290
=> 2 + 9n – 9 = 290
=> 9n = 297
=> n = 33
Thus, the 33 term of the AP is 290.