Find the number of terms in the sequence 4, 8, 16, 32, _____ 512.
Find the number of terms in the sequence 4, 8, 16, 32, _____ 512.
Explanation
GP series = 4, 8, 16, 32, ... 512.
FORMULA USED:
Tn = ar(n-1)
SOLUTION:
GP series = 4, 8, 16, 32, ... 512.
Tn = ar(n-1)
⇒ 512 = 4 × 2(n - 1)
⇒ 128 = 2(n - 1)
⇒ 27 = 2(n - 1)
Now comparing powers we obtain;
⇒ n - 1 = 7
⇒ n = 8