A man travels 1mile due east, 5mile due south, 2mile due east and finally 9miles due north. How far is the starting point?
Answer: 5miles
Explanation
Net eastward displacement =1+2=3 miles
Net northward displacement =−5+9=4 miles
Net displacement d=3i^+4j^
∣∣∣∣d∣∣∣∣=32+42=5 miles
Net eastward displacement =1+2=3 miles
Net northward displacement =−5+9=4 miles
Net displacement d=3i^+4j^
∣∣∣∣d∣∣∣∣=32+42=5 miles
