If (2x+3)(ax-5)=12x²+bx-15 for all values of x, what is the value of b?
If (2x+3)(ax-5)=12x²+bx-15 for all values of x, what is the value of b?
Explanation
| (2x+3)(ax-5)=12x^2+bx-15 2ax^2-10x+3ax-15=12x^2+bx-15 2ax^2-10x+3ax=12x^2+bx-15+15 2ax^2-10x+3ax=12x^2+bx 2ax^2+(3a-10)x=12x^2+bx Comparing Coefficient of x^2 2ax^2=12x^2 2a=12 a=12 Comparing Coefficient of x (3a-10)x=bx 3a-10=b By putting value of a=6 3(6)-10=b 18-10=b 8=b, answer |