Haider is 3 times as old as his son. After 10 years, the sum of their ages will be 76 years. Find Haider's present age.

Answer: 42 years

Let Haider's son's present age be x.

Haider's present age = 3x

After 10 years:

Son's age = x + 10

Haider's age = 3x + 10

The sum of their ages after 10 years will be 76:

x + 10 + 3x + 10 = 76

4x + 20 = 76

4x = 56

x = 14

Haider's present age = 3x = 3 × 14 = 42

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