Find the altitude of a trapezium if the length of two bases are 5.6 cm and 2.9 cm respectively. The area of the trapezium is 42 m²?
Find the altitude of a trapezium if the length of two bases are 5.6 cm and 2.9 cm respectively. The area of the trapezium is 42 m²?
Explanation
Given:
Area = 42 cm² (assuming the unit is consistent, but it's given as m² which seems incorrect given the base lengths are in cm. Let's proceed with cm² for calculation purposes)
Bases:
a = 5.6 cm
b = 2.9 cm
Formula:
Area = ((a + b) / 2) × height
42 = ((5.6 + 2.9) / 2) × height
42 = (8.5 / 2) × height
42 = 4.25 × height
height = 42 / 4.25
height = 9.88 cm