a street hawker sells two types of newspapers one for rs. 25 and the other for rs.40. if she sold 100 newspapers for rs. 2800. the newspapers she sold at rs.25 are---
Answer: 80
Explanation
0.25(x) + 0.40(100−x) =28
0.25 x + 40 − 0.40 x =28
0.25 x − 0.40 x =28−40
− 0.15 x = −12
x = 0.15/ 12 =80
***
ND18-1-2023
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